Find the area of equilateral triangle with radius length of 8. PLEASE answer in simplified radical form

16√3 units²

Step-by-step explanation:

I believe you meant, "with side length of 8."

Such a triangle has three equal angles, all 60 degrees.  Using this fact we can find the height of the triangle when the bottom side is horizontal:

sin Ф = (opposite side) / (hypotenuse), which here is

sin Ф = (height of triangle) / (8 units), from which we learn that

(height of triangle) = (8 units)(sin 60 degrees) = 8(√3)/2 = 4√3

Now we have all the information necessary to find the area of this triangle A = (1/2)(base)(height)  =  (1/2)(8 units)(4√3 units)  = 16√3 units²

okay so 15.15 *()5: +5/6

step-by-step explanation:

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.