In circle O, diameter AOB is drawn and point C is located on the circle such that CA=12 and CB=16. What is the length of the radius of circle O?

radius = 10

Step-by-step explanation:

As AB is the diameter of the circle, the angle ACB inscribes an arc of 180 degrees, so it is a 90 degrees angle, then the triangle ACB is a right triangle, with hypotenusa AB.

We can find the length of the diameter AB using the Pythagoras' theorem:

AB^2 = CA^2 + CB^2

AB^2 = 12^2 + 16^2 = 400

AB = 20

The radius of the circle is half the diameter, so the radius is 20 / 2 = 10

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!