From a window 20 feet above the ground, the angle of elevation to the top of another building is 35 degrees. The distance between the building is 52 feet. Find the height of the building nearest to the nearest tenth of a foot

  56.4 ft

Step-by-step explanation:

The tangent of the angle relates the opposite side (height above the window) to the adjacent side (distance between buildings) in the right triangle that models this geometry.

  Tan = Opposite/Adjacent

  tan(35°) = (height above window)/(distance between buildings)

  height above window = (52 ft)tan(35°) ≈ 36.4 ft

Added to the window height of 20 ft, the height of the other building is ...

  20 ft + 36.4 ft = 56.4 ft

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )