An object is launched at 9.8 meters per second from a 73.5 meter tall platform. The object’s
height (in meters) after seconds is given by the equation () = −.
− . + . . When
does the object strike the ground?
a. How can you solve this using a Table of Values?
b. How can you solve this using a graph?
c. How can you solve this algebraically?

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

b

step-by-step explanation:

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.