3х +2y = 12 + у
4y — 7t = 10
Solving systems of equations

numbers 3x + 2y = 12

y = x + 1

Substitution Method

Since y is already isolated in the second equation we can use that value, to substitute for y in the first equation.

3x + 2 (x + 1) = 12

3x + 2x + 2 = 12

5x = 12 − 2

5x = 10

x = 2

Substitute the computed value of x to the second equation to determine the value of y.

y = 2 + 1

y = 3

Elimination Method

3x + 2y = 12

x − y = −1

Multiply the second equation by 2 to eliminate

x or you can also multiply the second equation by 3 to eliminate y. However since it is easier to multiply by 2, I will follow the first method.

3x + 2y = 12

2x − 2y = −2

Adding the two equations eliminates the y variable.

5x = 10

x = 2

Substitute the computed value of x to the second equation to determine the value of y.

y = 2 + 1

y = 3

Solution Set:

(2,3)

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step-by-step explanation:

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