There are 4 apple trees which each have 10 pounds of apples, 5 peach trees
which ebch have 5 pounds of peaches, and 2 pear trees which each have 12
pounds of pears. If you pick all of this fruit, how many pounds of fruit will you
have?

pounds of fruit

89 pounds.

Step-by-step explanation:

4 apple trees with 10 pounds of apples each (4 times 10 = 40)

5 peach trees with 5 pounds of peaches each so (5 times 5 = 25)

2 pear trees with 12 pounds of pears each (2 times 12 = 24)

40 + 25 + 24 = 89.

89 lbs.

Step-by-step explanation:

Well, if you have 4 apple trees which each have 10 pounds of apples, you need to multiply 4 x 10 to get 40 lbs of apples altogether. (lbs = pounds)

Then, you multiply the 5 peach trees by the 5 pounds of peaches, which is 25 lbs of peaches altogether.

Next, you said there are 2 pear trees with 12 pounds of pears. You need to multiply 2 x 12 to get 24 lbs of pears.

Now here's the easy part. Just add 40 lbs of apples + 25 lbs of peaches + 24 lbs of pears.

You should now have 89 lbs of fruit in all.

I hope this answered your question. :)

your answer would be 12

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: