Create a data set of six values that meet the following criteria...
Mean: 6
Range: 7
Mode: 3
Median 6

A = {2, 6 ,6 , 6 , 7 ,9}

Step-by-step explanation:

As the mode is 3, we must have a number that repeats 3 times.

As the median is 6, the number in the middle must be 6

then with this we can construct a set with 3 times the number 6.

Now, knowing that the range is 7. the difference between the larger number and the smaller number is 7, so suppose the larger number is 9 and the smaller number is 2 (9 - 2 = 7)

Then the numbers in our set are:

2 6 6 6 9

lets find the last one.

We know that the mean is 6, then we have

6 = (1/6)*( 2 + 6 + 6 + 6 + 9 + x) = (1/6)(29 + x)

6*6 = 29 + x

36 - 29 = x

x = 7

Then our set is:

A = {2, 6 ,6 , 6 , 7 ,9}

Where the number in the middle is 6, the mean is 6, the mode is 3 and the range is 7

50

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )