In the United States, the mean age of men when they marry for the first time follows the normal distribution with a mean of 24.6 years. The standard deviation of the distribution is 2.8 years. For a random sample of 66 men, what is the likelihood that the age when they were first married is less than 25 years?

So we want to find this probability:

And using the normal standard distirbution or excel we got:

Step-by-step explanation:

Let X the random variable that represent the age of men married of a population, and for this case we know the distribution for X is given by:

Where and

We are interested on this probability

The sample size is n =66. We can use the z score to solve this problem:

If we find the z score for 25 we got:

So we want to find this probability:

And using the normal standard distirbution or excel we got:

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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