To solve the equation, Antwan uses the distributive property, combines like terms, then uses the addition and subtraction properties of equality to isolate the variable term on one side of the equation and the constant term on the other side. What are the possible values of the constant after Antwan has completed these steps? 3 (one-third x + 1) + 4 = negative 1 minus 4 (x + 3) –3 or 3 –3 or 5 –20 or 5 –20 or 20

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!