If 64ᵃ⁺ᵇ = 32 ᵃ⁺²ᵇ, then a=?

64^(a+b)= 32^(a+2b)

<=>(2^6)^(a+b) = (2^5)^(a+2b)

<=>2^(6a+6b) = 2^(5a+10b)

=> 6a + 6b = 5a + 10b

=> a = 4b

Hope this helps!

:)

no

step-by-step explanation:

3xy cannot be combined with the others

2x, -5x and x are like terms