Which box plot correctly displays the data set with a maximum of 24, a minimum of 3, a median of 15, an upper quartile of 19, and a lower quartile of 6?
A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 3 to 24, and the box ranges from 6 to 19. A line divides the box at 15.
A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 4 to 24, and the box ranges from 4 to 17. A line divides the box at 15.
A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 3 to 24, and the box ranges from 6 to 17. A line divides the box at 15.
A box-and-whisker plot. The number line goes from 0 to 25. The whiskers range from 3 to 24, and the box ranges from 4 to 19. A line divides the box at 15.

the answer is a if my teacher taught me correct

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

the first option i believe

step-by-step explanation:

mr. india