) An observer (O) is located 500 feet from a school (S). The observer notices a bird (B) flying at a 39° angle of elevation from his line of sight. How high is the bird flying over the school? You must show all work and calculations to receive full credit. (I would really appreciate it, thanks!)

 404.89 feet  

Step-by-step explanation:

Hi, since the situation forms a right triangle (see attachment) we have to apply the next trigonometric function.  

Tan α = opposite side / adjacent side

Where α is the angle of elevation of the bird (B), the opposite side (x) is the length of the bird above the ground, and the adjacent side is the distance between the school (S) and the observer (O).

Replacing with the values given:  

Tan 39 = x/ 50 0

Solving for x  

tan39 (500) =x  

x= 404.89 feet  

Feel free to ask for more if needed or if you did not understand something.  

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.