2. If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 feet

per second, then its height h after t seconds is given by the equations h(t) = -16° +128t (if air

resistance is neglected).

a. How long will it take for the rocket to return to the ground?

b. After how many seconds will the rocket be 112 feet above the ground?

C. How long will it take the rocket to hit its maximum height?

d. What is the maximum height?

Step-by-step explanation:

The given function is

The image attached shows the trajectory of the rocket in a height-time graph. Notice that the maxium point reached is (4, 256), which means after 4 seconds, the rocket has a maximum height of 256 feet. (c) and (d)

Additionally, a parabola is symmetrical, which means it takes the same time going up or down, therefore the rocket reaches the ground after 8 seconds. (a)

Now, when the rocket is 112 feet above the ground, we have

Where we need to solve for

Using a calculator, we have the solutions and , which means after 1 second and 7 second, the rocket is 112 feet above the ground. (b)

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere