El MCM de dos números es 200 y su MCD es 4. Si uno de ellos es 8, ¿cuál es el otro número?

The other number is 100.

Step-by-step explanation:

The least common multiple (LCM) of two numbers is 200

The greatest common denominator (GCD) is 4.

One of the numbers is 8, which is the other number?

Ok:

First, we can write 8 as: 2*2*2 = 2^3 = 2*4

Now, the minimal common denominator can be any number that is written in the form

x = 4*a*b..

where a, b etc are prime numbers.

We also know that

LCD(a,b) = a*b/GCD(a,b)

LCD(8,x) = 8*x/GCD(8, x)

200 = 8*x/4

x = 200*4/8 = 100

the other number is 100.

your answer is the frist one

hop i

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.