Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are the zeros of g(x)? (show your work!)

Enter your answers in the blanks:

g(x) = 3()()

Zeros: and

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

In this question:

So

So

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

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step-by-step explanation:

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you answer is a

step-by-step explanation: