Find the measure of center that best represents each set data round to the nearest tenth if necessary number of parking spaces used: 46,39,40,45,44,68,51

Now we can calculate the standard deviation :

And replacing we got:

We can see the the standard deviation is lower than the sample mean and then we can conclude that the sample mean would be a good decription for a measure of center.

Other reason to no use the median is because we don't have enough sample size to assume that this measure represent very well the measure of center.

Step-by-step explanation:

For this case we have the following data:

46,39,40,45,44,68,51

We can begin calculating the sample mean with this formula:

And replacing we got:

Now we can calculate the standard deviation :

And replacing we got:

We can see the the standard deviation is lower than the sample mean and then we can conclude that the sample mean would be a good decription for a measure of center.

Other reason to no use the median is because we don't have enough sample size to assume that this measure represent very well the measure of center.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

∠cbe and ∠deb are same-side interior angles.

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