Suzanne wants to put a fence around her square garden. If the garden covers an area of 49ft^2, how many feet of fencing does she need

The area for a square is given by:

And we can find the dimension for one side like this:

Replacing we got:

Then since we are interested in the how many feet of fencing does she need, we can find the perimeter given by:

and replacing we got:

Step-by-step explanation:

For this case we know that Suzanne want to put a fance around a square garden with an area of 49 ft^2

The area for a square is given by:

And we can find the dimension for one side like this:

Replacing we got:

Then since we are interested in the how many feet of fencing does she need, we can find the perimeter given by:

and replacing we got:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

ιт ιѕ 6/23

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ!