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Question 4
What happens when the player performs the trial (rolling two dice) N times? Perform the trial by simulating it N times for these values of N: 5,
10,20, and 50. In this simulation, you will roll two dice (or, strictly speaking, click the button that simulates the roll), write down the numbers
shown on the faces (a pair of numbers obtained on each roll is a outcome), and calculate the product of the two numbers for each roll.
N is the number of times you roll the two dice. In the table below, fill in the value of Ne, where Ng is the number of times event (the product of
the two numbers rolled is odd) occurs.
Then calculate the fraction of times it occurs, f = mg correct to two decimal places.
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N NEF
NE
M
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10
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50
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2:34 PM

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

he has 140 chickens because he has 10 times more chickens than ducks and he has 14 ducks so 14*10=140

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: