The distance it takes a truck to stop can be

modeled by the function

Determine the value off, rounded to the nearest

hundredth.

DONE

d(u)=2.1502

64.4f

d = stopping distance in feet

v=nial velocity in miles per hour

= a constant related to friction

When the truck's initial velocity on dry pavement is

40 moh its stopping distance is 138 ft

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4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4

step by step solution :

step   1   :

1.1     4 = 22

(4)3 = (22)3 = 26

equation at the end of step   1   :

  ((23) • 26)2

step   2   :

equation at the end of step   2   :

  (23 • 26)2

step   3   :

final result :

  218

ya

$113.42

i hope that is right.

step-by-step explanation: