You are a driver of a dump truck with a trailer (dump bin) that is 21 feet long, 8 feet wide, and 6 feet tall Daily, you haul full

loads of dirt from one location to another. The dump bin can hold dirt equivalent to 1.2 times its capacity

What is the minimum number of trips needed to haul 20,000 cubic feet of dirt?

16

17

19

20

24

(B)17

Step-by-step explanation:

The dump truck is 21 feet long, 8 feet wide, and 6 feet tall.

Volume of the dump truck=21 X 8 X 6=1008 cubic feet

Since the dump bin can hold dirt equivalent to 1.2 times its capacity,

Volume of dirt the truck can hold=1.2 X 1008=1209.6 cubic feet

If the truck wants to haul 20,000 cubic feet of dirt.

Minimum number of trips=20000/1209.6=16.53 Trips

We round this up to 17 since there is no half trip.

Therefore, the minimum number of trips needed to haul 20,000 cubic feet of dirt is 17.

yes

yes yes yes

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b