The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Which values of x hold true for the inequality?

3x ＞ 37

x ＞ 12.333

Thus, 13 and 15 satisfy

Step-by-step explanation:

hope this helps

All integers greater than 12 (13 onwards) satisfy the inequality

Step-by-step explanation:

x + x + 1 + x + 2 > 40.

3x + 3 > 40

3x > 37

x > 12.3333

All integers greater than 12 (13 onwards) satisfy the inequality

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)