What is the solution to the system of equations below?
{2y=x+6
{3x=y+7

x=4, y=5

Step-by-step explanation:

2y=x+6

3x=y+7

If you subtract 6 from both sides of the first equation, x will be isolated and you can plug it into the second equation. The new first equation is 2y-6=x, which when plugged into the second equation yields:

3(2y-6)=y+7

6y-18=y+7

5y=25

y=5

x=4

Hope this helps!

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

a: 1/6, j: 1/4

step-by-step explanation: you are welcome