Let Eequals={Bold e 1e1, Bold e 2e2, Bold e 3e3} be the standard basis for set of real numbers Rℝ3, Bequals={Bold b 1b1, Bold b 2b2, Bold b 3b3} be a basis for a vector space V, and T : set of real numbers Rℝ3 right arrow→ V be a linear transformation with the property that Upper T (x 1 comma x 2 comma x 3 )Tx1, x2, x3equals=(x 2 minus x 3 )x2−x3Bold b 1b1plus (x 1 plus x 3 )+x1+x3Bold b 2b2plus (x 2 minus x 1 )+x2−x1Bold b 3b3.a. Find the change-of-coordinates matrix from Upper B to Upper A. b. Find left bracket Bold x right bracket Subscript Upper A for Bold x equals Bold b 1 minus 4 Bold b 2 plus 4 Bold b 3.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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step-by-step explanation:

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches