A ladder 13m long is placed on the ground in such a way that it touches the top of a vertical wall 12m high. find the distance of the foot of the ladder from the bottom of the wall

by applying Pythagoras theorem;

the ladder(13m) acts as hypotenuse

the wall (12m) acts as height

the distance between the the two is the base

therefore

a² + b² = c²

b²= c²- a²

b²= 169 - 144

b² = 25

√b² = √25

b= 5m

the distance is 5m

answer:

c 60% on edg

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: