Someone please help me with an explanation please! Asap would be nice :)

HOW TO DETERMINE SLOPE AND Y-INTERCEPT: Use the instructions below to answer this question.

EQUATION: y=x-3

-------------------------------------------------

FINDING THE Y-INTERCEPT:

Do this simply by finding the number your graph starts at on the Y-Axis (vertical line)! In this case, it's at -3!

FINDING SLOPE:

Remember that slope is rise over run ()

RISE = How far the line goes up and down.

RUN = How far the line goes left or right.

HOW DO I FIND IT? All you have to do is count both rise and run from one point on the line to another! WARNING: The point must hit at a vertex, it cannot be counted if it is in the center of the box, or anywhere that does not touch the edge. I also suggest starting from the Y-Intercept and counting.

GOING LEFT OR DOWN: This is a positive number

GOING RIGHT OR UP: This is a negative number.

(You will see how this applies, below, yayyyy)

CALCULATING OUR NUMERATOR, AKA RISE:

Starting from the y, to get to the next point on the line, you can see we have to go down three. This means our numerator is -3!

CALCULATING OUR DENOMENATOR, AKA RUN:

Starting from where we just stopped, we must continue getting to the next point, and to do that, you can see we have to go to the right four! This means our denomenator is 4!

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2