Can someone please help me with this problem?

f'(1) = 2

Step-by-step explanation:

f(x) = 2x^2 -2x +3

Take the derivative

f'(x) = 2 * 2x - 2 * 1

f'(x) = 4x -2

f'(1) = 4(1) -2

      =4-2

       =2

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)