Suppose that triangle ABC is dilated to A'B'C' by a scale factor of 4 with a center of dilation at the origin. What is the distance from the center of dilation to the midpoint of B'C'?

The distance from the center of dilation to the midpoint of B'C' would be an increase in the initial distance from the origin to midpoint of BC by a scale factor of 4.

Step-by-step explanation:

Dilation is a transformation process that increases the size of a given figure by a factor. This implies that every coordinate of the initial figure would be multiplied by the factor to produce the new figure.

In the given question, dilation of the triangle at the origin by a factor of 4 implies that the coordinates of the triangle increased by a factor of 4. Thus, the distance from the center of dilation to the midpoint of B'C' would be an increase in the initial distance from the origin to midpoint of BC by a scale factor of 4.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option