Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered 3 from the second bag? Wh

Complete question:

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

1 2 3 4 5 6

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 2 from the first bag and the tile numbered three from the second bag?

1/36

Step-by-step explanation:

Number of tiles in each bag = 6

Probability of drawing tile numbered 2 from the first bag and the tile numbered 3 from the second

Probability of drawing number 2 from first bag :

P(numbered 2) = (required outcome / possible outcome)

P(numbered 2) = 1/6

Probability of drawing number 2 from first bag :

P(numbered 3) = 1/6

Since they are independent events :

P(drawing 2 from bag one and 3 from bag 2) :

1/6 × 1/6 = 1/36

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

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