The paper cup is 9 cm tall and the circular opening has a radius of 2.5 cm.

What is the minimum amount of paper needed to make the paper cup to the nearest whole cm² assuming no overlap in the paper?

181cm^2

Step-by-step explanation:

The minimum amount of paper needed to make the cup to the nearest whole number will be = to the surface area of the cylinder = A=2πrh+2πr2.

Where π= 22/7, r = 2.5cm, h = 9cm

A = 2×22/7×2.5×9+2×22/7×2.5×2.5

A= 141.428+39.285

A= 180.713

A = 181cm^2

step-by-step explanation:

i have no idea

answer with step-by-step explanation:

a. ∠j is supplementary to ∠k - true:

(opposite angles of a trapezoid are supplementary which means that they add up to 180 degrees)

b. kl is parallel to jm - true:

(opposite sides are parallel to each other in a trapezoid)

c. jk is perpendicular to kl - false:

(clearly, jk does not make a right angle with kl)

d. jk is parallel to lm - false:

(jk and lm are two lines opposite in direction to each other so they cannot be parallel)

e. ∠j is congruent to ∠m - true:

(the angles on each side of the base are congruent)

f. ∠j is congruent to ∠k - false:

(the angles on the same side but opposite side of the base are not congruent)