Which function has the same range as fx)=-2 VX-3 +8?
g(x)=√x-3-8
g(x)=√x-3+8
g(x)=-x+3+8
g(x)=√x-3-8

First lets find the range of -2 sqrt(x - 3) + 8

x cannot be < 3   or f(x) would not be real  

when x = 3 f(x) = 8 

and for all other values of x  f(x) will tend to  - infinity

range is [8, - infinity)

if we do same for the 4 choices we'll see that  - sqrt(x - 3)+8  will have same range

or this:     answer is:

g(x)=-\sqrt{x+3}+8    Step-by-step explanation:

we have

f(x)=-2\sqrt{x-3}+8 using a graphing tool

see the attached figure N

The domain is the interval > [3, ∞)

The range is the interval > (-∞, 8]

Verify the range of each case by graphing tool

see the attached figure N using a graphing tool

see the attached figure N

The domain is the interval > [3, ∞)

The range is the interval > (-∞, 8]

Verify the range of each case by graphing tool

see the attached figure N 2 case A) g(x)=\sqrt{x-3}-8 The range is the interval > [-8,∞) case B) g(x)=\sqrt{x-3}+8 The range is the interval > [8,∞) case C) g(x)=-\sqrt{x+3}+8

The range is the interval >(-∞, 8] > is the solution (same range that f(x))  case D) g(x)=-\sqrt{x-3}-8

The range is the interval > (-∞, -8]

step-by-step explanation:

16 is the absolute value

step-by-step explanation: