You have a bag of marbles. 5 marbles are blue, 4 marbles are red, and 2 marbles are yellow. What is the probability that you pull a red marble and then a yellow marble, when the first marble is not replaced before pulling the second

1. 4/11 2. 2/10 or 1/5

Step-by-step explanation:

The first thing you need to do is find the total number of marble and then break it into their probabilities. 4+2+5= 11

Red: 4/11, Yellow: 2/11 and Blue: 5/11

So for 1. you just need the probability of pulling a red marble with we already figured out, 4/11.

For the second part you're looking for the probability of pulling a yellow marble after a red was pulled and not replaced. When we take one out and don't replace it the only thing that changes is the total and the number for that color so, the probabilities change to: Red: 3/10, Yellow: 2/10 and Blue: 5/10.

So now you have the probability of pulling a yellow if a red was pulled first without being replaced.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

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