The volume of a box 4 in. wide, 2 in. high, and 5 in. long is:
A. 22 in.
B. 40 cu. in.
C. 11 cu. in.
D. 40 sq. in.
E. 11 sq. in.

Volume of box = 40 cu. in.

Step-by-step explanation:

Width of box = 4 in.

Height of box = 2 in.

Length of box = 5 in.

Volume of box = Width × Height × Length

= 4 × 2 × 5

= 40 cu. in.

2,600 divided by 80 = 32.5

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.