The landing restuarant order 200 flowers for mother day. the orderd carnation at 1.50$,Rose's at 5.75$and the daisies at 2.60$ each. They order carnation mostly and 20 fewer Rose's than daisies. The total orders came $589.50. How many of each type of flower was ordered?

She ordered 80 carnations, 50 roses, and 70 daisies.

Step-by-step explanation:

Let x = number of carnations, y = number of roses, and z = number of daisies.  This problem gives us three equations.

First, remember that we multiply the price of each flower by the number bought then add up the subtotals, that gives the total amount paid.

Therefore,

1.50x + 5.75y + 2.60z = 589.50

Second, the sum of the numbers purchased is the total bought. Therefore,

x + y + z = 200

Finally, there are 20 fewer roses than daisies. Therefore,

y = z - 20

If you substitute z - 20 in for y in the first two equations, you can rewrite them so they only have x and z.

1.50x + 5.75(z - 20) + 2.60z = 589.50

1.50x + 5.75z - 115 + 2.60z = 589.50

1.50x + 8.35z = 704.50

x + (z - 20) + z = 200

x + 2z - 20 = 200

x + 2z = 220

If you solve the rewrite second equation for x, you get x = 220 - 2z.  Therefore, you can substitute 220 - 2z in for x in the rewritten first equation, and then solve for z.

1.50 (220 - 2z) + 8.35z = 704.50

330 - 3z + 8.35z = 704.50

330 + 5.35z = 704.50

5.35z = 374.50

z = 70

If you have z = 70, then x = 220 - 2(70) = 80 and y = 70 - 20 = 50.

She ordered 80 carnations, 50 roses, and 70 daisies.

*HOPE THIS HELPED!!! :D)

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.