F a triangle has a side length of 10, 12 and 15 units respectively, what type of triangle is it acute right obtuse or no solution

Acute.

Step-by-step explanation:

Using the Triangle Inequality Theorem you know that the sum of the lengths of two sides of a triangle are greater than the length of the third side.

Using this we can narrow it down that this DOES have a solution, since 10+12>15.

Now, we can determine if this triangle is a right triangle using the Pythagorean Theorem. C is the longest length.

If c^2= a^2+b^2, then it is a right triangle.

If c^2< a^2+b^2 then it is an acute triangle.

If c^2>a^2+b^2 then it is an obtuse triangle.

We can now substitute. (A and B are interchangeable, but C is the longest length.

A=10

B=12

C=15

A^2=100

B^2=144

C^2=255

We can now figure out that this triangle is acute because A^2+ B^2 (244) < C^2 (255).

Hope this helps!

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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