In ΔVWX, v = 47 cm, w = 11 cm and x=38 cm. Find the measure of ∠W to the nearest 10th of a degree.

When we know all 3 sides we use the law of cosines

a = 47  

b = 11  

c = 38

cos (A) = (b^2+c^2-a^2)  / (2bc)

cos (A) = -0.7703349282

Angle A = 140.38

cos (B) = (a^2 + c^2 -b^2) / (2ac)

cos (B) =  0.9888017917

Angle B = 8.5826  degrees

cos (C) = (a^2 + b^2 -c^2) / 2ab

cos (C) = 0.8568665377

cos (C) = 31.033 degrees

Angle W would be the smallest angle so it equals

31.033 degrees or rounded to nearest tenth

31.03

Step-by-step explanation:

180

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b