2(x+3)^2+2(y)^2=32 what is the center point of the circle and how long is the radius

center (-3, 0)radius 4

Step-by-step explanation:

The standard form equation of a circle is ...

  (x -h)^2 +(y -k)^2 = r^2 . . . . . . . . . center at (h, k), radius r

Divide your given equation by 2 to put it into standard form:

  (x +3)^2 +y^2 = 16

Comparing to the above, we see ...

h = -3k = 0r = √16 = 4

The center point of the circle is (-3, 0); the radius is 4 units long.

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.