A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1960 mailboxes this week. If each mailbox has dimensions as shown in the figure below, how many square meters of aluminum will be needed to make these mailboxes? In your calculations, use the value 3.14 for pi , and round up your answer to the next square meter.

  7088 m²

Step-by-step explanation:

The area of the half-cylinder is half the area of a cylinder with the same dimensions. This half-cylinder has a radius of 0.3 m and a length of 0.8 m, so its area is ...

  A = πr(r +l) = π(0.3 m)(0.3 m+0.8 m) = 0.33π m² ≈ 1.0362 m²

The area of the bottom part of the box is the sum of its lateral area and its base area.

  lateral area = Ph = (2(0.6m +0.8m))(0.75 m) = 2.1 m²

  base area = lw = (0.8 m)(0.6 m) = 0.48 m²

The total area is then ...

  total area = half-cylinder area + lateral area + base area

  = 1.0362 m² +2.1 m² +0.48 m²

  = 3.6162 m²

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The area for 1960 mailboxes will be 1960 times this area, or ...

  area for week's production = 1960 × 3.6162 m² = 7087.752 m²

It will take about 7088 square meters of aluminum to make these mailboxes.

the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

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