What is the of A in a partial fraction decomposition below?

8x+28/ (x-1)(x+2)(x+3) = A/x-1 + B/x+2 + C/x+3

3

Step-by-step explanation:

(8x + 28) / ((x − 1) (x + 2) (x + 3)) = A / (x − 1) + B / (x + 2) + C / (x + 3)

Multiply both sides by (x − 1) (x + 2) (x + 3).

8x + 28 = A (x + 2) (x + 3) + B (x − 1) (x + 3) + C (x − 1) (x + 2)

If x = 1:

8 + 28 = A (3) (4)

36 = 12A

A = 3

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12