Pls help 100 points

Consider this dilation.

(a)
Is the image of the dilation a reduction or an enlargement of the original figure? Explain.

(b)
What is the scale factor? Explain.

The letters M,S,V are the original image.

The letters M’, S’, V’ are the displayed image.

You can see that M’, S’,V’ is a smaller image, so it was a reduction.

The length of line MS is 9 units.

The length of M’S’ is 6 units.

The dialation is 6/9 = 2/3

(a) reduction

(b) 2/3

Step-by-step explanation:

(a) The original figure is called ΔMSV, while the dilation is called ΔM'S'V'. Because we can see that M'S'V' is clearly much smaller than MSV, we know that the image is a reduction of the original.

(b) We simply need to find the ratio of one side of M'S'V' to one side of MSV. Look at M'S': the length is just 4 - (-2) = 6 (this is because it's a completely horizontal line). The length of MS is 6 - (-3) = 9.

So, the scale factor is: 6 / 9 = 2/3.

the answer is (-4,-4)

hope this ! : d

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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