And one baseball season, peter hit twice the difference of the number of homeruns ellis hat and six. all together, they hit 18 home runs period how many homeruns did each player hit that season

Let Peter's hit be x and Ellis' runs be y.
x = 2(y - 6) . . . (1)
x + y = 18 . . . (2)

Putting (1) into (2) gives,
2y - 12 + y = 18
3y = 18 + 12 = 30
y = 30/3 = 10
x = 2(10 - 6) = 2(4) = 8

Therefore, Peter hit 8 home runs and Ellis' hit 10 home runs.

Do you have a picture? ?