The perimeter of a rectangle is 40cm. If the length were doubled and the width halved, the perimeter would be increased by 16cm. Find the dimensions of the original rectangle.
Create a linear system to model the situation.
Determine, by substitution, the dimensions of the original rectangle (sketch and label rectangles to help) PLS SHOW ALL WORK NEED ASAP

The dimensions of the original rectangle are Length =12cm, Width=8cm

Step-by-step explanation:

Let the length of the rectangle be x

Let the width of the rectangle be y

The perimeter of a rectangle is 40cm.

2(x+y)=40

Divide both sides by 2

x+y=20

If the length were doubled(2x) and the width halved(y/2), the perimeter would be increased by 16cm,i.e.(40+16)cm

Therefore:

Divide both sides by 2

From the first equation, x=20-y.

Substitute x=20-y into

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option