The sum of two consecutive even integers is 226. what is the larger integer?

Since the two consecutive integers are even, one of them will be represented by x and one will be x + 2.

x + (x + 2) = 226   Combine like terms
2x + 2 = 226   Subtract 2 from both sides
2x = 224   Divide
x = 112

The two integers are 112 and 114. You can double check by  them

112 + 114 = 226

We represent the first integer with y and the second even integer equal to y + 2. Using the given statement, we translate it into equation: y  + y+2 = 226. we add like terms, y and y equal then to 2y  + 2 = 226. y is equal to 112 while the other integer has to be equal to 114. The answer is 114.

X=14 hope it !