Acircle has its center at (-1, 2) and a radius of 3 units. what is the equation of the circle?
a) (x - 1)2 + (y + 2)2 = 3
b) (x + 1)2 + (y - 2)2 = 3
c) (x + 1)2 + (y + 2)2 = 9
d) (x + 1)2 + (y - 2)2 = 9

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

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