What algebraic expression must be subtracted from the sum of y2+5y−1

y

2

+

5

y

−

1

and 3y2−2y+4

3

y

2

−

2

y

+

4

to give 2y2+7y−2

2

y

2

+

7

y

−

2

as the result?

2y² -4y +5

Step-by-step explanation:

First you need to find the sum of y²+5y-1 and 3y²-2y+4

(y²+5y-1) + (3y²-2y+4) => y²+3y²+5y-2y-1+4

                                  =4y²+3y+3

Next is to subtract 2y²+7y-2 from the sum calculated above in order to  find the algebraic expression asked in the exercise

4y²+3y+3 -(2y²+7y-2) => 4y²-2y²+3y-7y+3+2

                                   =2y² -4y +5

Therefore, the algebraic expression asked must be 2y² -4y +5

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

understand that i don't know the answers

will someone answer his question