Which expressions are equivalent to \dfrac{2^5}{6^5}

6

5

2

5



start fraction, 2, start superscript, 5, end superscript, divided by, 6, start superscript, 5, end superscript, end fraction ?

Choose 2 answers:

Choose 2 answers:

(Choice A)

A

\dfrac{1}{3}

3

1



start fraction, 1, divided by, 3, end fraction

(Choice B)

B

3^{-5}3

−5

3, start superscript, minus, 5, end superscript

(Choice C)

C

(-4)^{-5}(−4)

−5

left parenthesis, minus, 4, right parenthesis, start superscript, minus, 5, end superscript

(Choice D)

D

2^5\cdot 6^{-5}2

5

⋅6

−5

2, start superscript, 5, end superscript, dot, 6, start superscript, minus, 5, end superscript

We have been given an expression . We are asked to choose the expressions, which are equivalent to our given expression.

Using exponent property , we can rewrite our given expression as:

Upon looking at our given choices, we can see that option D is the correct choice.

Let us simplify our given expression.

Upon cancelling out from numerator and denominator, we will get:

Using exponent property , we will get:

Therefore, option B is a correct choice as well.

add an image, and i will answer

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92