Mathematics
Mathematics, 07.05.2020 10:00, dondre54

Using calculus, the area of the region under y=1/(1+x^2), above the x-axis and between x=a and x=b is tan^(-1)b - tan^(-1)a. Use this result, shown in the figure, to find the area of the region under y=1/(1+x^2), above the x-axis, and between a=-1 and b=1


Using calculus, the area of the region under y=1/(1+x^2), above the x-axis and between x=a and x=b i

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Using calculus, the area of the region under y=1/(1+x^2), above the x-axis and between x=a and x=b i...

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