B. What is the probability that you don’t roll a 2 or a 3, P (NOT a 2 or 3)? Explain your reasoning. (2 points possible)
1. In a game, if you roll a 2 or a 3 on a 6-sided number cube, you lose a turn. NOTE: This is just using one number cube.

The probability that you don’t roll a 2 or a 3 = 2/3

Step-by-step explanation:

Formula for Probability = Number of Possible Outcomes / Number of events

We are told in the question that it is just a one number cube. This means that :

We have the Probability of rolling the 6 sided cube and obtaining, 1, 2, 3, 4, 5, and 6.

We are told in the question to find the probability of not rolling a 2 or 3.

Hence, this means

Probability( not a 2 or 3) = Probability( of a 1 or 4 or 5 or 6).

Therefore,

Probability (of rolling a 1) = 1/6

Probability (of rolling a 4) = 1/6

Probability (of rolling a 5) = 1/6

Probability (of rolling a 6) = 1/6

Therefore, Probability( not a 2 or 3) = Probability( of a 1 or 4 or 5 or 6) = P(1) + P(4) + P(5) + P(6)

= 1/6 +1/6 + 1/6 + 1/6

= 4/6

= 2/3.

Therefore, the probability that you did not roll a 2 or 3 ( i.e P( not 2 or 3)) = 2/3

i think the answer is true

step-by-step explanation: