Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Use the equation 0 = ?16t2 + 38.8t + 3 to find the number of seconds t that the balloon is in the air.

t = 2.5 s

Step-by-step explanation:

Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Its equation is :

The above equation is a quadratic equation. The general equation is :

Here, a = 16, b = 38.8 and c = 3

The solution of quadratic equation is given by :

So, at t = 2.5 s the balloon is in air.

d is correct

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: