2. The temperature of the ocean at Huntington Beach can vary up to 8.6°F from the
average temperature of 75°F. Write and solve an absolute value equation to find the temperature extremes of the ocean.
temperature extremes of the ocean.

Let x represent temperature of the ocean.

We have been given that the temperature of the ocean at Huntington Beach can vary up to 8.6°F from the  average temperature of 75°F. We are asked to write an absolute value equation to find the temperature extremes of the ocean.

We will use tolerance formula to solve our given problems.

Upon substituting our given values in above formula, we will get:

Therefore, our required inequality would be .

Using absolute value rule , we will get:

Therefore, the temperature extremes of the ocean would be .

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt