I need help with this

Step-by-step explanation:

Consider the product ...

  (x +a)(x +b) = x^2 +(a+b)x +ab

You will notice that the linear term (a+b)x has a coefficient (a+b) that is the sum of the factors of the constant term (ab).

For problems like this, it is useful to be able to factor the constant term, so you can choose the factors with the appropriate sum.

Signs are important. If the constant is positive, its factors will have the same sign, both positive or both negative. If the constant is negative, its factors will have opposite signs.

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1. b^2 +13b +36

Factors of 36 are ...

  36 = 1·36 = 2·18 = 3·12 = 4·9 = 6·6

The sums of these are 37, 20, 15, 13, and 12. So, the factor pair we're looking for is 4 and 9. The factorization is ...

  = (b +4)(b +9)

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2. c^2 +4c -45

The middle term is positive, so the larger magnitude factor will be positive. Factors of -45 are ...

  -45 = -1·45 = -3·15 = -5·9

Sums of these factors are 44, 12, 4. So, the factor pair we're looking for is -5 and 9. The factorization is ...

  = (c -5)(c +9)

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3. k^2 +5k +6

  6 = 1·6 = 2·3 . . . . sums are 7 and 5  ⇒  factors of interest are 2 and 3

  = (k +2)(k +3)

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.